Como cambiar de forma exponencial a logaritmica?
log8(1/4)=-2/3
la formula para transformarlo a logaritmo es la siguiente a=b^x<>logb(a)=x
por lo tanto:
8^-2/3=1/4<>log8(1/4)=-2/3
= 8^(- 2/3) → you know that: x^(- n) = 1/x^(+ n) = 1/x^(n)
= 1/8^(2/3)
= 1/8^[2 * (1/3)] → you know that: x^(ab) = [x^(a)]^(b)
= 1/[8^(2)]^(1/3)
= 1/[64]^(1/3) → you know that: 64 = 4 * 4 * 4 = 4^(3)
= 1/[4^(3)]^(1/3) → recall: [x^(a)]^(b) = x^(ab)
= 1/4^[3 * (1/3)]
= 1/4^(1)
= 1/4
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log8(1/4)=-2/3
la formula para transformarlo a logaritmo es la siguiente a=b^x<>logb(a)=x
por lo tanto:
8^-2/3=1/4<>log8(1/4)=-2/3
= 8^(- 2/3) → you know that: x^(- n) = 1/x^(+ n) = 1/x^(n)
= 1/8^(2/3)
= 1/8^[2 * (1/3)] → you know that: x^(ab) = [x^(a)]^(b)
= 1/[8^(2)]^(1/3)
= 1/[64]^(1/3) → you know that: 64 = 4 * 4 * 4 = 4^(3)
= 1/[4^(3)]^(1/3) → recall: [x^(a)]^(b) = x^(ab)
= 1/4^[3 * (1/3)]
= 1/4^(1)
= 1/4