Elevación de términos a sus respectivas potencias y cálculo de raíces: 

(4/9)(16/81)(27/8)(-2/2)

Supresión de términos:

(4/9)(2/3)(-1)

-8/27

Es la b)

Revísalo!

= (2/3)^(2) * (3/2)^(- 4) * (3/2)^(3) * [³√(- 8) / √(√16)] → you know that: √16 = 4 because 4² = 16

= (2/3)^(2) * (3/2)^(- 4) * (3/2)^(3) * [³√(- 8) / √(4)] → you know that: √4 = 2 because 2² = 4

= (2/3)^(2) * (3/2)^(- 4) * (3/2)^(3) * [³√(- 8) / 2] → you know that: ³√x = x^(1/3)

= (2/3)^(2) * (3/2)^(- 4) * (3/2)^(3) * [(- 8)^(1/3) / 2] → you know that: - 8 = (- 2) * (- 2) * (- 2) = (- 2)^(3)

= (2/3)^(2) * (3/2)^(- 4) * (3/2)^(3) * [{(- 2)^(3)}^(1/3) / 2] → you know that: {x^(a)}^b = x^(ab)

= (2/3)^(2) * (3/2)^(- 4) * (3/2)^(3) * [(- 2)^{3 * (1/3)} / 2] → you can simplify

= (2/3)^(2) * (3/2)^(- 4) * (3/2)^(3) * [(- 2)^(1) / 2] → you can simplify

= (2/3)^(2) * (3/2)^(- 4) * (3/2)^(3) * [- 2 / 2] → you can simplify

= (2/3)^(2) * (3/2)^(- 4) * (3/2)^(3) * (- 1) → you can simplify

= - (2/3)^(2) * (3/2)^(- 4) * (3/2)^(3) → you know that: x^(a) * x^(b) = x^(a + b)

= - (2/3)^(2) * (3/2)^[(- 4) + (3)] → you can simplify

= - (2/3)^(2) * (3/2)^(- 1) → you know that: x^(- 1) = 1/x^(1) = 1/x

= - (2/3)^(2) * [1/(3/2)] → you know that: 1/(a/b) = b/a

= - (2/3)^(2) * (2/3) → you know that: x = x^(1)

= - (2/3)^(2) * (2/3)^(1) → recall: x^(a) * x^(b) = x^(a + b)

= - (2/3)^[(2) + (1)]

= - (2/3)^(3) → you know that: (a/b)^(x) = [a^(x) / b^(x)]

= - [2^(3) / 3^(3)]

= - 8/27 → b) answer