El ejercicio dice:
Si se sabe que: Log 2 = 0.301, Log 3 = 0.4771, Log 5 =0.699, Log 7 = 0.8451.
Entonces sin hacer uso de la calculadora cual es el resultado de: Log 0.84
primero 0.84=84/100=21/25=(7*3)/(5*5)
entonces log(0.84)=log(7*3/5*5)=
log(7*3)-log(5*5)=
log7+log3-(log5+log5)=
log7+log3-2log5=
0.8451+0.4771-2*(0.699)
.84 es aproximadamente 6/7
Log(.84)=log(6/7)=log(6)-log(7)=log(2*3)-log(7)=log(2)+log(3)-log(7)=.301+.4771-.8451=-.067
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primero 0.84=84/100=21/25=(7*3)/(5*5)
entonces log(0.84)=log(7*3/5*5)=
log(7*3)-log(5*5)=
log7+log3-(log5+log5)=
log7+log3-2log5=
0.8451+0.4771-2*(0.699)
.84 es aproximadamente 6/7
Log(.84)=log(6/7)=log(6)-log(7)=log(2*3)-log(7)=log(2)+log(3)-log(7)=.301+.4771-.8451=-.067