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Rewrite as

y = 2x + 8

Now use y=mx+b

Where m=slope and b=y-intercept.

So on your graph you would start at (0,8) and put a dot. Then from that point go up 2 units and over 1 unit and put another dot. From that spot go up 2 units and over 1 unit and put another dot.

You should have dots at the three points: (0,8) and (1,10) and (2,12).

Now line up the three dots and draw the line. And don't forget to put arrows at each end of the line.

:)

Graph Y 2x-8

First rewrite this as y=mx+b

In this case:

y=2x+8

Now to graph this, it's probably easier to find the y and x intercepts and just connect the dots.

So

Make y=0 to find the x interecept:

0=2x+8

Minus 8 and divide by 2:

-4=x

So you have the point: (-4,0)

Now find the y intercept by making x=0

y=2(0)+8

so (0,8) is the y intercept.

Now just connect the dots and draw arrows on each side.

Have a nice day :)

first you write down your equation. next step is to ADD 2x to both sides because -2x + 2x = 0 which will leave you with y on the left side and 8 + 2x because you added 2x to this side as well) whatever you do to one side you must do to the other. so you end up with y=8+2x which makes the graphing a lot easier. now on your graph put a dot on the point that marks (0,8) because that is your y intercept (8) the you use 2 as your slop and go up 2 over one because 2 in a faction reads 2/1 so you go up two over 1. if after youve switched the numbers to something like y=8+2x and it is 8-2x make sure you go down 2 and over one ps over 1 is directed at the right

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/// f'=2=k/2sqrtx ksqrtx=2x+8 x=4 k=8

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RE:

How do I graph y-2x=8?

Math help please

graph 2x8