Note that both arcsin and arccos refer to reference angles, and they have the same absolute degree measurements of 22.62°.
cos(-22.62 + 22.62)
==> cos(0)
==> 1
I hope this helps!
1} your question is cos(arcsin(-5/13)+arccos(12/13)) = ?
2} the arcsin and arccos both refer to a 22.62 degree reference angle.
this dimension of triangle is used a lot.
3} arcsin(-5/13) = -22.62 degrees
4} arccos(12/13) = 22.62 degrees
5} arcsin(-5/13)+arccos(12/13) = -22.62 degrees + 22.62 degrees = 0 degrees
6} you're looking for cos(0)
7} cos(0) = 1
pretty mean way of saying 1, isn't it!
the answer is 1.
honestly, it really is.
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Note that both arcsin and arccos refer to reference angles, and they have the same absolute degree measurements of 22.62°.
cos(-22.62 + 22.62)
==> cos(0)
==> 1
I hope this helps!
1} your question is cos(arcsin(-5/13)+arccos(12/13)) = ?
2} the arcsin and arccos both refer to a 22.62 degree reference angle.
this dimension of triangle is used a lot.
3} arcsin(-5/13) = -22.62 degrees
4} arccos(12/13) = 22.62 degrees
5} arcsin(-5/13)+arccos(12/13) = -22.62 degrees + 22.62 degrees = 0 degrees
6} you're looking for cos(0)
7} cos(0) = 1
pretty mean way of saying 1, isn't it!
the answer is 1.
honestly, it really is.